If a and B are the zeroes of the
polynomial 21x² -x - 2, find a
quadratic polynomial whose zeroes are 2a and 2B.
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Given:-
Zeroes of polynomial p(x) = 21x^2-x-2=0 is a and b
Here,
21x^2-x-2=0
=>21x^2-(7-6)x-2=0
=>21x^2-7x+6x-2=0
=>7x(3x-1)+2(3x-1)=0
=>{3x-1)(7x+2)=0
Now,
3x-1=0 ; 7x+2=0
=>3x=1 ; =>7x=-2
Therefore, x=1/3 ; x=-2/7
Before we considered that x=a ; x=b
So,
a=1/3 ; b=-2/7
Now,
2a=2{1/3) ;2b2(-2/7)
Hence, 2a=2/3 ; 2b=-4/7
I HOPE THAT IT HELPS YOU.
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