Question

if a and b are the zeroes of the polynomial 3x²-5x-2, then evaluate a²+b², 1/a + 1/b, a³b+ab³.

Answer 1

Step-by-step explanation:

$3 {x}^{2} - 5x - 2 = 0$

$3 {x}^{2} - 6x + x - 2 = 0$

$3x(x - 2) + 1(x - 2) = 0$

$(3x + 1)(x - 2) = 0$

so the values of a and b are 2,-1/3

substitute and get the answer

hope this will help u