If a and b are the zeroes of the polynomial 5x²-12x-3, the what is the value of [1/a+1/b]
a) -4. b) -3
c) 3. d) 4
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Answer:
a
Step-by-step explanation:
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GIVEN :–
• a and b are the zeroes of the polynomial 5x² - 12x - 3 = 0 .
TO FIND :–
• Value of (1/a) + (1/b) = ?
SOLUTION :–
▪︎We know that –
• Sum of roots = -(coffieciant of 'x')/(coffieciant of x² )
=> a + b = -(12)/5
=> a + b = - 12/5
• Product of roots = (constant term)/(coffieciant of x²)
=> (a)(b) = -(⅗)
=> a.b = - (⅗)
▪︎ Now Let's find –
= (1/a) + (1/b)
= (a + b)/(a.b)
= [-(12/5)]/(3/5)
= - (12/3)
= -4
▪︎ Hence , Value of (1/a) + (1/b) = -4
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