If a and B are the zeroes of the polynomial p(x) = x2 - p(x + 1)-c such that (a + 1) (B + 1) = 0, the c=
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p(x)=x2-p(x+1)-c
A.T.Q
(a+1)(b+1)=0
so from here
We got the value of a and b
so value of a=-1
b=-1
we put the value of a and b in the first eq.
so,
p(-1)=(-1)2-p(-1+1)-c
1+p-p-c=0
1-c=0(p and negative p will be cancelled)
so,. c=1
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