Question

if a and b are the zeroes of the polynomial p(x) =x²-p(x+1)-c such that (a+1((B+1)=0,thec=_______​

Answer 1

ANSWER:-

${x}^{2} - px - p - c$

${x}^{2} - px - (p + c)$Sum of zeroes = p

Product of zeroes = -(p+c)

According to question,

$( \alpha + 1)( \beta + 1) = 0$

$\alpha ( \beta + 1) + 1( \beta + 1)$

$\alpha \beta + \alpha + \beta + 1$

$\alpha \beta = product \: of \: zeroes$

$\alpha + \beta = sum \: of \: zeroes$

So,

-(p+c) + p + 1 =0

- p - c + p + 1 = 0

- c = -1

c = 1. ANSWER!!!

Answer 2

Step-by-step explanation:

So,

-(p+c) + p + 1 =0

- p - c + p + 1 = 0

- c = -1

c = 1. ANSWER!!!