Question

If a and b are the zeroes of the polynomial x2–11x+30 ,Find the value of (a cube) and (b cube)

Answer 1

Answer:

125 ; 216.

Step-by-step explanation:

x² - 11x + 30 = 0

x² - 5x - 6x + 30 = 0

x(X - 5)-6(x - 5) = 0

(X - 5) (X - 6) = 0

X - 5 = 0

X = 5

Hence , a = 5

x - 6 = 0

X = 6

b = 6

a³ = (5)³

a³ = 125

b³ = (6)³

b³ = 216.

Answer 2

Answer:

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Step-by-step explanation:

x²-11x+30

x²-6x-5x+30 = 0

x(x-6)-5(x-6) = 0

(x-6)(x-5) = 0

x-6 = 0 | x-5 = 0

x = 6 | x =5

Therefore,5 and 6 are zeroes of the given polynomial.

a = 5 and b = 6

a³=5³

b³=6³