Question

If a and b are the zeroes of the polynomial x²+8x+6n,form a polynomial whose zeroes are 1/a² and 1/b² Pls answer this question fast...

Answer 1

Answer:

36x² - 52x + 1 = 0

Step-by-step explanation:

If a and b are the zeroes of the polynomial x²+8x+6n

therefore ,

a + b =-b/a = -8      

ab = c/a = 6

let the zeroes of the second polynomial

1/a² , 1/b²

sum of these zeroes ,

1/a² + 1/b² = (b² + a²)/a²b²        [(b + a)² = a² + b² + 2ab = a² + b² = 52]

52 /36

product of these two zeroes ,

1/a².1/b² = 6² = 1/36

therefore the new polynomials is

x² - (1/a² + 1/b²)x + 1/a².1/b²

x² - 52/36.x  + 1/36 = 0

36x² - 52x + 1 = 0