Question

if a and b are the zeroes of the polynomial x2-(p+1)x+c,such that(a+1) (B+1) =0, then find the value c'.​

Answer 1

Answer:

if A and B Are the zeroes as if we take B= -1alsoA then, (-1+1)(-1+1)=0

0=0

P=0

so according to question.

x square -(0+1)x+c=0

x square -x+c=0

-x square +x=c

if we take x as 1 then, (-1)(-1)+1=0

0=0.

so c value is -x square +x

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