if a and b are the zeroes of the polynomials f(x)=x-p(x+1)-c, then (a +1)(+1) =
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Value of c is 1.
Explantion is attached.
Hope it helps.
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Answer:
We have,
f(x)=x
2
−p(x+1)−c=0
f(x)=x
2
−px−(p+c)=0 (1)
Since,
α,β are the zeroes of the above polynomial.
So,
α+β=p
αβ=−(p+c)
Since,
(α+1)(β+1)=0
αβ+α+β+1=0
−p−c+p+1=0
−c+1=0
c=1
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