If 'a' and 'b' are the zeroes of the polynomials of p(x)= x^2+x-1. Then find the value of 1/a+1/b.
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Answer:
The correct answer is 0
Step-by-step explanation:
p(x)=x^2+x-1
x^2+1x-1x-1
x(x+1)-1(x+1)
x=1 or x=-1
1/1+(-1/1)
1/1-1/1=0
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