If A and B are the zeroes of the quadratic polnomial f (x)= x^(2) +x -2 , find the value of 1/A -1/B....
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According to given sum,
A, B are the zeroes of the polynomial.
so the sum of zeroes = A+B =>-1
product of zeroes= AB=> -2
Given that ,
1/A-1/B =>(A-B)/AB..........¡
(A-B)^2= (A+B)^2-4AB
(A-B)^2=(-1)^2 -4 (-2)
(A-B)^2=1+8=9
A-B=3
substitute this value in equation i
(A-B)/AB=> 3/-2
=>-3/2
:-)Hope it helps u.
A, B are the zeroes of the polynomial.
so the sum of zeroes = A+B =>-1
product of zeroes= AB=> -2
Given that ,
1/A-1/B =>(A-B)/AB..........¡
(A-B)^2= (A+B)^2-4AB
(A-B)^2=(-1)^2 -4 (-2)
(A-B)^2=1+8=9
A-B=3
substitute this value in equation i
(A-B)/AB=> 3/-2
=>-3/2
:-)Hope it helps u.
krishiv8190:
Thanks
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