Question

If A and B are the zeroes of the quadratic polnomial f (x)= x^(2) +x -2 , find the value of 1/A -1/B....


Pls solve it asap

Answer 1

According to given sum,

A, B are the zeroes of the polynomial.

so the sum of zeroes = A+B =>-1

product of zeroes= AB=> -2

Given that ,

1/A-1/B =>(A-B)/AB..........¡

(A-B)^2= (A+B)^2-4AB

(A-B)^2=(-1)^2 -4 (-2)

(A-B)^2=1+8=9

A-B=3


substitute this value in equation i

(A-B)/AB=> 3/-2

=>-3/2

:-)Hope it helps u.