Question

If a and B are the zeroes of the
quadratic polynomial ax + bx + c, form
a quadratic polynomial whose zeroes
are a+1/b and b+1/a​

Answer 1

Answer:

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Step-by-step explanation:

A+B= -b/a

AB= c/a

A+1/B + B+1/A

After calculation,

=(A+B)^2 -2AB+A+B /AB

=(-b/a)^2 -2c/a -b/a. /c/a

After calculation,

=b^2 -2ac-ab /ac

A+1/B * B+1/A

= AB+A+B+1 /AB

=c/a -b/a +1 /c/a

=c-b+a /c

Polynomial

acx^2 -(b^2 -2ac-ab)x +a(c-b+a)

Hence proved