If a and b are the zeroes of the quadratic polynomial f(x)= x2-1 find a quadratic polynomial whose zeros are 2a/b and 2b/a
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Answer:f[x] = x^2 -1 = [x+1] [x-1]
1 and -1 are zeroes
now a=1 and b= -1
2a/b = -1 and 2b/a = -1
so p[x] = [x+1] [x+1]
p[x] = x^2 + 2x +1
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