if a and B are the zeroes of the quadratic polynomial p(x)=x2-8x+15 then find the value of a^3+b^3
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2
Answer:
refer the attachment
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Answered by
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Answer: 152
Step-by-step explanation: p(x)=x^2-8x+15
Therefore we have to solve the quadratic equation.
x²-8x+15=x²-3x-5x+15
x(x-3)-5(x-3)=0
By this we get the factors of the equation as (x-3) and (x-5)
x=3,5. Therefore we get the value a & b as 3,5.
So by substituting the value of a & b as 3 & 5 in equation a³+b³
we get 27+125 which is 152.
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