Question

If a and B are the zeroes of the quadratic polynomial p(y) = 5y2 – 7y + 1, find the value of
1 1
+
a B​

Answer 1

Step-by-step explanation:

find y using p(y) = 0

It will give you two values of y that will be equal to a and B.

thereafter, find 11 + aB by putting a and B.

any confusion? dm me

Answer 2

Answer:

• 5y^2-7y+1
• a=5, b=-7, c=1
• we know that's sum of zero=-b/a
• a+b=7/5equation number first
• product of zero=c/a
• ab=1/5 equation number second
• now, 1/a+1b
• b+a/ba
• from equation first and second
• 7/5÷1/5
• =7