Math, asked by khushirani1983, 1 year ago

if a and b are the zeroes of x^2+4x+3. find the value of a^3 +b^3

Answers

Answered by ona4295
2

Answer:

-28

Step-by-step explanation:

x² +4x +3 =0

⇒x²+3x+1x +3.

=0

⇒x(x+3) + 1(x+3)

=0

⇒(x+1)( x+3)

=0

x=-1;-3

Therefore a=-1

And b=-3

a³+b³=-1³-3³=-1-27=-28

Answered by Anonymous
5

Answer :-

The value of a³ + b³ is - 28.

Solution :-

x² + 4x + 3

To find the zeroes of x² + 4x + 3 equate it to zero

⇒ x² + 4x + 3 = 0

⇒ x² + 3x + x + 3 = 0

⇒ x(x + 3) + 1(x + 3) = 0

⇒ (x + 1)(x + 3) = 0

⇒ x + 1 = 0 or x + 3 = 0

⇒ x = - 1 or x = - 3

The zeroes of the x² + 4x + 3 are - 1 and - 3

a and b are zeroes

So a = - 1 and b = - 3

Substituting a = - 1, a = - 3 in a³ + b³

a³ + b³

= (- 1)³ + (-3)³

= - 1 + (-27)

= - 1 - 27

= - 28

Therefore the value of a³ + b³ is - 28.

Similar questions