if a and b are the zeroes of x^2+4x+3. find the value of a^3 +b^3
Answers
Answered by
2
Answer:
-28
Step-by-step explanation:
x² +4x +3 =0
⇒x²+3x+1x +3.
=0
⇒x(x+3) + 1(x+3)
=0
⇒(x+1)( x+3)
=0
x=-1;-3
Therefore a=-1
And b=-3
a³+b³=-1³-3³=-1-27=-28
Answered by
5
Answer :-
The value of a³ + b³ is - 28.
Solution :-
x² + 4x + 3
To find the zeroes of x² + 4x + 3 equate it to zero
⇒ x² + 4x + 3 = 0
⇒ x² + 3x + x + 3 = 0
⇒ x(x + 3) + 1(x + 3) = 0
⇒ (x + 1)(x + 3) = 0
⇒ x + 1 = 0 or x + 3 = 0
⇒ x = - 1 or x = - 3
The zeroes of the x² + 4x + 3 are - 1 and - 3
a and b are zeroes
So a = - 1 and b = - 3
Substituting a = - 1, a = - 3 in a³ + b³
a³ + b³
= (- 1)³ + (-3)³
= - 1 + (-27)
= - 1 - 27
= - 28
Therefore the value of a³ + b³ is - 28.
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