if a and b are the zeroes of x2 +7x + 12,then find the value of 1/a + 1/b + 2ab
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x^2 +7x +12
x^2 +4x+3x +12
x(x+4) +3(x+4)
(x +3) (x+4)
x = -3 & x= -4
let a= -3 & b = -4
ATQ
1/a+1/b+2ab
(1/-3) +(1/-4) +2(-3) (-4)
-1/3-1/4+24
-4-3+288/12
281/12 Ans
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hope this answer is helpful friend have a nice day
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