Math, asked by aashish220543, 1 year ago

if A and B are the zeros of a quadratic polynomial such that a + b equal to 24 and a minus b equal to 8 find the quadratic polynomial having a and b as its zeros​

Answers

Answered by suklarc2010
8

Answer:x^2-24x+128

Step-by-step explanation:

As a&b are the zeroes, the quadratic equation will be x ^2-(a+b)x+ab.

Given a+b=24

So a^2+2ab+b^2=576

a^2+b^2=576-2ab

a-b=8

a^2-2ab+b^2=64

a^2+b^2=64+2ab

Equating both equations,

576-2ab=64+2ab

4ab=512

ab=128

The required polynomial is

X ^2-24x+128

Answered by suklarc2010
3

Answer:x^2-24x+128

Step-by-step explanation:

As a&b are the zeroes, the quadratic equation will be x ^2-(a+b)x+ab.

Given a+b=24

So a^2+2ab+b^2=576

a^2+b^2=576-2ab

a-b=8

a^2-2ab+b^2=64

a^2+b^2=64+2ab

Equating both equations,

576-2ab=64+2ab

4ab=512

ab=128

The required polynomial is

X ^2-24x+128

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