Math, asked by shinjinibose14, 1 year ago

If A and B are the zeros of the polynomial 3x^2+11x-4 then what is the value of a^2+b^2?​

Answers

Answered by sagarsaxena279
2

Answer:

145 / 9

Step-by-step explanation:

 3x^2 + 11x - 4

= 3x^2 + 12x - x - 4

= 3x(x+4) - 1(x+4)

= (3x-1) (x+4)

= x = -4 or 1/3

so, a^2 + b^2 = 16 + 1/9 = 145/9

Answered by Chandershekhar38
3

Answer:

Step-by-step explanation:

For zeroes :-

3x^2+11x-4=0

=>3x^2+12x-x-4=0

=>3x(x+4)-1(x+4)=0

=>(3x-1)(x+4)=0

=>3x-1=0 or x+4=0

=>x=1/3 or x=-4

Thus,a=1/3 & b=-4

So,a^2+b^2=(1/3)^2+(-4)^2

=1/9+16

=1+9*16/9

=1+144/9

=145/9

pls mark it as brainliest....

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