If A and B are the zeros of the polynomial 3x^2+11x-4 then what is the value of a^2+b^2?
Answers
Answered by
2
Answer:
145 / 9
Step-by-step explanation:
3x^2 + 11x - 4
= 3x^2 + 12x - x - 4
= 3x(x+4) - 1(x+4)
= (3x-1) (x+4)
= x = -4 or 1/3
so, a^2 + b^2 = 16 + 1/9 = 145/9
Answered by
3
Answer:
Step-by-step explanation:
For zeroes :-
3x^2+11x-4=0
=>3x^2+12x-x-4=0
=>3x(x+4)-1(x+4)=0
=>(3x-1)(x+4)=0
=>3x-1=0 or x+4=0
=>x=1/3 or x=-4
Thus,a=1/3 & b=-4
So,a^2+b^2=(1/3)^2+(-4)^2
=1/9+16
=1+9*16/9
=1+144/9
=145/9
pls mark it as brainliest....
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