Question

If a and b are the zeros of the polynomial f(s)=s2-18s+77, then find the value of a^3+b^3.

Answer 1

${s}^{2} - 18s + 77 = 0 \\ (s - 11)(s - 7) = 0 \\ s = 11 \: \: or \: \: 7 \: \: are \: the \: zeros \\ {a}^{3} + {b}^{3} = {11}^{3} + {7}^{3} =1674$