Question

If a and B are the zeros of the polynomial of x²+3x-2 then find the value of a² ß³ + a³ß² ?​

Answer 1

Answer:

The answer will be 12.

Step-by-step explanation:

Given,

      α and β are the zeroes of polynomial x²+3x-2.

= α² ß³ + α³ß²

= α² ß³ + αß²

= α²ß² (α + ß)

= (αß)² (α + ß)                                   (i)

From the polynomial, we can deduce that;

            α + ß = -b/a;

                      = -(-3) / 1;

                      = 3                              (ii)

and,          αß = c/a;

                      = -2/1;

                       = -2;                          (iii)

From eq. (i), (ii) and (iii), we can conclude that;

                   = (-2)² (3);

                   = 4 * 3;

                   = 12.

That's all.