if a and b are the zeros of the polynomial x^2 + 6x +9 then form a polynomial whose zeroes are -a and -b.
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x2-6x+9 is the equation with roots -a and -b
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Given equation :- x² + 6x + 9
Let's factorise it by middle term splitting :- x² + 6x + 9
x² + 3x + 3x + 9
x ( x + 3 ) + 3 ( x + 3 )
( x + 3 ) ( x + 3 )
• ( x + 3 ) = 0
x = ( - 3 )
• ( x + 3 ) = 0
x = ( - 3 )
• The new equation having Zeros as :-
So, the Zeros are 3
Sum of the Zeros are :-
3 + 3 = 6
Product of the Zeros are :-
3 × 3 = 9
♯ To form the quadratic equation we have formula as :-
x² - ( sum of Zeros )x + ( product of Zeros)
Putting value in it !!
x²-6x+9 is the required quadratic equation!!
Step-by-step explanation:
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