Math, asked by bharatphed, 11 months ago

if a and b are the zeros of the polynomial x^2 + 6x +9 then form a polynomial whose zeroes are -a and -b.

Answers

Answered by Anonymous
1

Step-by-step explanation:

x2-6x+9 is the equation with roots -a and -b

Attachments:
Answered by binodiya6
1

Answer:

Given equation :- x² + 6x + 9

Let's factorise it by middle term splitting :- x² + 6x + 9

x² + 3x + 3x + 9

x ( x + 3 ) + 3 ( x + 3 )

( x + 3 ) ( x + 3 )

• ( x + 3 ) = 0

x = ( - 3 )

• ( x + 3 ) = 0

x = ( - 3 )

• The new equation having Zeros as :-

So, the Zeros are 3

Sum of the Zeros are :-

3 + 3 = 6

Product of the Zeros are :-

3 × 3 = 9

♯ To form the quadratic equation we have formula as :-

x² - ( sum of Zeros )x + ( product of Zeros)

Putting value in it !!

x²-6x+9 is the required quadratic equation!!

Step-by-step explanation:

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