Question

if A and B are the zeros of the polynomial x square - 2 X + 8 then the sum of their reciprocal is​

Answer 1

Step-by-step explanation:

Given If A and B are the zeros of the polynomial x ^2 - 2 x + 8 then the sum of their reciprocal is

• Given A and B are the zeroes of the polynomial p(x) = x^2 – 2x + 8
• Compare this with p(x) = ax^2 + bx + c, we get a = 1, b = - 2, and c = 8
• Now sum of zeroes = - b/a
• So A + B = - (-2) / 1
•                 = 2 ----------------------1
• Product of zeroes = c/a
• AB = 8/1
•     = 8 -------------------------2
• Now sum of reciprocals of zeroes will be
• = 1/A + 1/B
• = A + B / AB
• = 2/8
• = 1/4
• Therefore sum of reciprocals of the zeroes = 1/4  

Reference link will be

https://brainly.in/question/3425013