If a and b are the zeros of the polynomial x2-4x+3 then form a quadratic equation whoes zeros are 3a and 3b
Answers
Answered by
11
Hey there,
x=3a
then a=x/3
(x/3)²-4(x/3)+3
=x²/9-4x/3+3
Multiplying by 9, we get-
x²-12x+27
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07161020
Ace
x=3a
then a=x/3
(x/3)²-4(x/3)+3
=x²/9-4x/3+3
Multiplying by 9, we get-
x²-12x+27
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
Answered by
10
Hi !
p(x) = x² - 4x + 3
sum of zeroes = a + b = -(-4) = 4
product of zeros = ab = 3
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A quadratic polynomial is of the form :-
x² - (sum of zeros)x + (product of zeroes)
sum of zeros = 3a + 3b = 3(a+b)
= 3*4 = 12
product = 3a*3b = 9b
= 9*3
= 27
Hence, the polynomial is :-
x² - 12x + 27
p(x) = x² - 4x + 3
sum of zeroes = a + b = -(-4) = 4
product of zeros = ab = 3
--------------------------------------------------------------------------------
A quadratic polynomial is of the form :-
x² - (sum of zeros)x + (product of zeroes)
sum of zeros = 3a + 3b = 3(a+b)
= 3*4 = 12
product = 3a*3b = 9b
= 9*3
= 27
Hence, the polynomial is :-
x² - 12x + 27
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