If a and b are the zeros of the polynomials p(x) =3 x²-4x-7 then from a quadratic polynomial whoes zeroes are 1/a and 1/ b
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Answer:
7x²+10x +3
Step-by-step explanation:
3x²-4x-7=3x²+3x-7x-7
=3x(x+1)-7(x+1)
=(3x-7)(x+1)
the zeroes are -7/3 and -1
a=-7/3
b=-1
then the quadratic polynomial whose zeros are 1/α and 1/β is
sum of zeros= 1/ a+ 1/b
=-10/7
product of zeros=1/a×1/b
=3/7
then the resulting equation is
7x²+10x +3
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