if a and b are the zeros of the polynomialx2 +8x+6n form a polynomial whose zeroes are 1/a2 and 1/b2
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1
Answer:
the answer will be
1/a²=1/64
1/b2=1/36 OK friend by
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ANSWER
f(x)=6x2+x−2
a,b are its zero's / roots.
a+b=6−1,ab=6−2=−1/3
ba+ab=aba2+b2=ab(a+b)2−2ab
=(−1/3)(−1/6)2−2(−1/3)=−1/3361+32
=−(121+2)=12−25
f(x)=6x2+x−2
a,b are its zero's / roots.
a+b=6−1,ab=6−2=−1/3
ba+ab=aba2+b2=ab(a+b)2−2ab
=(−1/3)(−1/6)2−2(−1/3)=−1/3361+32
=−(121+2)=12−25
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