Question

if a and b are the zeros of the quadratic polynomial at f (x) =x2-p(x+1)-c find the value of (a+1(b+1​

Answer 1

Step-by-step explanation:

x²-px-p-c = 0

a+b = p

ab = -p-c

now, (a+1)(b+1)

= ab+a+b

=-p-c+p

= -c

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