Question

If a and B are the zeros of the quadratic polynomial f(x) = 6x² + x - 2, find the value of alpha/beta + beta/alpha​

Answer 1

Answer:

Let’s first solve the equation to get our zeroes of the equation i.e. alpha and beta.

6 x^2 + x − 2 = 0

6 x^2 + 4 x − 3 x − 2 = 0

2 x (3 x + 2) − (3 x + 2)=0

Which gives us two equations,

2 x − 1= 0

x = 1/2(alpha)

3 x + 2= 0

x = −2/3(beta)

So, the value of alpha/beta and beta/alpha will be -3/4 and -4/3, adding both of them gives the solution as -25/12.

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Step-by-step explanation:

Answer 2

Answer:

-23/12 is the answer.

Step-by-step explanation:

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