Math, asked by Riddhesh7727, 9 months ago

If a and B are the zeros of the quadratic polynomial f(x) = x2 - x - 4, find the value of 1/a+1/B-aB​

Answers

Answered by rupeshpradhan07
1

Answer:

15/4 is the correct answer

Answered by stalwartajk
1

Answer:

value of the 1/a+1/B-aB is 15/4

Step-by-step explanation:

Quadratic equation, f(x) = x2 - x - 4

α and β are zero for this quadratic polynomial equation

We have to find- (1/α + 1/β) - αβ

So, sum of the roots = α+β = -b/a = -(-1)/1 = 1

      Product of the roots = α.β = -4/1 = -4

Now putting the values of α and β in given equation

(1/α + 1/β) - αβ

((α+β/αβ) - αβ

1/(-4) - (-4)

-¼ + 4

(-1+16)/4

15/4

Therefore the value of (1/α + 1/β) - αβ of the given polynomial quadratic equation f(x) = x2 - x - 4 is 15/4

Steps to you have to remember to solve this types questions

Note down all given data

Put formula of sum of the roots and Product of the roots

Solving

To know more about others questions of this type click on the given links

https://brainly.in/question/6185700

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