If a and B are the zeros of x² + 5x + 8 = 0, then what is the value of (a + b)?
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Given:-
- p(x) = x² + 5x + 8
- α and β are the roots of p(x)
To find:-
- The value of (α + β)
Answer:-
We know that, for a polynomial ax² + bx + c, having roots x₁ and x₂,
- Sum of roots = x₁ + x₂ = - (coefficient of x)/(coefficient of x²) = -b/a
- Product of roots = x₁x₂ = (constant term)/(coefficient of x²) = c/a
On comparing p(x) = x² + 5x + 8 with the standard form, that is, ax² + bx + c, we get,
- a = 1
- b = 5
- c = 8
So,
sum of roots = -b/a
→ α + β = -5/1
→ α + β = -5 Ans.
Extra knowledge:-
For a cubic polynomial ax³ + bx² + cx + d, having roots α, β and γ,
- α + β + γ = -b/a
- αβ + βγ + γα = c/a
- αβγ = -d/a
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