Question

If A and B are two digits of a number
394AB such that this number is divisible
by 60 then A+B is equal to? (Number
System)​

Answer 1

Step-by-step explanation:

  Given If A and B are two digits of a number  394AB such that this number is divisible  by 60 then A+B is equal to?

• Given Sum of all digits of number 394AB
•                                   = 3 + 9 + 4 + A + B
• Taking B = 0 we get
•                                = (3 + 9 + 4 + A + 0)
•                                 = 16 + A
• If it should be divisible by 3 we need to add 2, 5 or 8
• So let A = 2, we get sum of numbers as 16 + 2 = 18 which is divisible by 3.
• So number will be 39420 which is divisible by 60
• Therefore A + B = 2 + 0 = 2
• Now let A = 5
• Sum of numbers will be 16 + A = 16 + 5 = 21 divisible by 3.
• So number formed will be 39450 which is divisible by 60.
• Therefore A + B = 5 + 0 = 5
• Now let A = 8
• Sum of numbers will be 16 + A = 16 + 8 = 24 which is divisible by 3
• So number formed will be 39480 which is divisible by 60
• So the value of (A + B) will be either 2,5 or 8.

Reference link will be

https://brainly.in/question/15601805