If A and B are two events associated with a random experiment such that P(A) = 0.3, P(B) = 0.4 and P(A ∪ B) = 0.5, find P(A ∩ B).
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Solution:-
Given A and B are two events
And, P(A) = 0.3 P(B) = 0.5 P(A ∪ B) = 0.5
We need to find P(A ∩ B).
By definition of P(A or B) under axiomatic approach(also called addition theorem) we know that:
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
∴ P(A ∩ B) = P(A) + P(B) – P(A ∪ B)
⇒ P(A ∩ B) = 0.3 + 0.4 – 0.5
= 0.7 – 0.5 = 0.2
∴ P(A ∩ B) = 0.2
Hope it helps you..
Answered by
2
Answer:
0.2 is answer.
p(AUB)=P(A)+P(B)-p(a intersection b)
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