Question

If A and B are two events of an experiment such that P(AUB) = 3/4, P(A) = 7/20, then find
P(B). given that A and B are mutually exclusive?​

Answer 1

Answer:

P(A)=1/2,P(B)=p

P(AUB)=3/5

i) Mutually exclusive P(A∩B)=0

P(AUB)=P(A)+P(B)-P(A∩B)

3/5=1/2+p-0

p=1/10

ii)Independent events P(A∩B)=P(A)*P(B)=p/2

P(AUB)=P(A)+P(B)-P(A∩B)

3/5=1/2+p-p/2

p=1/5

Answer 2

Answer:

Step-by-step explanation: