if A and B are two events p(A) =1/4,p(b)=1/2p(A,B)=1/8. Find (i) p(a or b) (ii) p(not a and not b)
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Answer:
Given P(A)=
2
1
P(B)=
4
1
⟹P(B)=
4
2
=
2
1
P(A∩B)=
8
1
P(A∪B)=P(A)+P(B)−P(A∩B)=
4
1
+
2
1
−
8
1
=
8
2+4−1
=
8
5
P(not A and not B)=P(A
′
∩B
′
)=1−P(A∪B)=1−
8
5
=
8
8−5
=
8
3
Step-by-step explanation:
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