Math, asked by chuky2711, 1 year ago

If a and b are two events such that p(a) = 0.2, p(b) = 0.6 and p(a /b) = 0.2 then the value of p(a /~b) is

Answers

Answered by MaheswariS
4

\textbf{Given:}

\mathsf{P(A)=0.2,\;P(B)=0.6,\;P\left(\dfrac{A}{B}\right)=0.2}

\textbf{To find:}

\textsf{The value of}

\mathsf{P\left(\dfrac{A}{\overline{B}}\right)}

\textbf{Solution:}

\mathsf{Consider,}

\mathsf{P\left(\dfrac{A}{B}\right)=0.2}

\mathsf{\dfrac{P(A{\cap}B)}{P(B)}=0.2}

\mathsf{\dfrac{P(A{\cap}B)}{0.6}=0.2}

\implies\mathsf{P(A{\cap}B)=0.12}

\mathsf{Now,}

\mathsf{P\left(\dfrac{A}{\overline{B}}\right)}

\mathsf{=\dfrac{P(A{\cap}\overline{B})}{P(\overline{B})}\right}

\mathsf{=\dfrac{P(A)-P(A{\cap}B)}{1-P(B)}}

\mathsf{=\dfrac{0.2-0.12}{1-0.6}}

\mathsf{=\dfrac{0.08}{0.4}}

\mathsf{=\dfrac{8}{40}}

\mathsf{=\dfrac{1}{5}}

\implies\boxed{\mathsf{P\left(\dfrac{A}{\overline{B}}\right)=\dfrac{1}{5}}}

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Answered by Anonymous
6

\textbf{Given:}

\mathsf{P(A)=0.2,\;P(B)=0.6,\;P\left(\dfrac{A}{B}\right)=0.2}

\textbf{To find:}

\textsf{The value of}

\mathsf{P\left(\dfrac{A}{\overline{B}}\right)}

\textbf{Solution:}

\mathsf{Consider,}

\mathsf{P\left(\dfrac{A}{B}\right)=0.2}

\mathsf{\dfrac{P(A{\cap}B)}{P(B)}=0.2}

\mathsf{\dfrac{P(A{\cap}B)}{0.6}=0.2}

\implies\mathsf{P(A{\cap}B)=0.12}

\mathsf{Now,}

\mathsf{P\left(\dfrac{A}{\overline{B}}\right)}

\mathsf{=\dfrac{P(A)-P(A{\cap}B)}{1-P(B)}}

\mathsf{=\dfrac{0.2-0.12}{1-0.6}}

\mathsf{=\dfrac{0.08}{0.4}}

\mathsf{=\dfrac{8}{40}}

\mathsf{=\dfrac{1}{5}}

\implies\boxed{\mathsf{P\left(\dfrac{A}{\overline{B}}\right)=\dfrac{1}{5}}}

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