Question

If a and b are two events such that p is equal to 0.2 PB is equal to 0.4 and p a union b is equal to 0.5 then the value of b a by b is

Answer 1

Option (b) - P(AlB) = 0.25

Step-by-step explanation

The correct question is

If A and B are two events such that P(A) = 0.2 , P(B) = 0.4 and P(A ∪ B) = 0.5, then value of P(A|B) is ?

(a) 0.1 (b) 0.25 (c) 0.5 (d) 0.08

Given :

P(A) = 0.2

P(B) = 0.4

P(AUB) = 0.5

To find : P(AlB)

P(AlB) = P(A∩B)\P(B)

P(AUB) = P(A) +P(B) - P(A∩B)

0.5 = 0.2 + 0.4 - P(A∩B)

P(A∩B) = 0.1

$\text{P(AlB)} = \frac{0.1}{0.4}$

∴P(AlB) = 0.25 which is option (b)

To Learn More

1. evaluate P(AUB) if; 2P(A)=P(B)=5/13 AND P(A/B)=2/5

brainly.in/question/7896421

2.  A and B are two events such that P(A) = 0.54, P(B) = 0.69 and P(A∩B) = 0.35.  Find (i) P(A∩B) (ii) P(A′∩B′) (iii) P(A∩B′) (iv) P(B∩A′)

brainly.in/question/1842395