If A and B are two matrices such that AB=B and BA=a, then find the value of A2+B2
Answers
Answered by
33
☆☆heya your answer is here☆☆
Your mistake is that you have assumed that A and B are invertible, which does not have to be the case.
A² + B² = A(BA) + B(AB)
= (AB)A + (BA)B
= BA + AB
= A + B.
It's certainly not true that A or B has to be the identity. For instance, they could both be the 0 matrix, or the matrix
[1 0]
[0 0].
The interesting question is whether there is a solution with B not equal to A. If we can show that B must always equal A, then your other solutions would be valid (though they can be simplified to 2A and 2B).
However, this turns out not to be the case. Take A =
[0 0]
[a 1]
and B =
[0 0]
[b 1]
for any two different numbers a and b. Then AB = B and BA = A, but A² + B² is
[0 0]
[a+b 1]
which is equal to A+B, but not equal to 2AB (=2B), or 2BA (=2A).
Your mistake is that you have assumed that A and B are invertible, which does not have to be the case.
A² + B² = A(BA) + B(AB)
= (AB)A + (BA)B
= BA + AB
= A + B.
It's certainly not true that A or B has to be the identity. For instance, they could both be the 0 matrix, or the matrix
[1 0]
[0 0].
The interesting question is whether there is a solution with B not equal to A. If we can show that B must always equal A, then your other solutions would be valid (though they can be simplified to 2A and 2B).
However, this turns out not to be the case. Take A =
[0 0]
[a 1]
and B =
[0 0]
[b 1]
for any two different numbers a and b. Then AB = B and BA = A, but A² + B² is
[0 0]
[a+b 1]
which is equal to A+B, but not equal to 2AB (=2B), or 2BA (=2A).
Answered by
0
Answer:
A^2+B^2
=AA+BB
=A(BA)+B(AB)
=(AB)A+(BA)B
=BA+AB
=A+B
Hope this will help you
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