Math, asked by sniacaptsmaheshkud, 1 year ago

If a and b are two numbers occurring in the prime factorization of 360 which is given by 630 = 2 * a * a *b *7 What is the value of a + b?

Answers

Answered by RyanPCH
1
a^2*b*2*7=630
a^2*b=45
45 = (1,3,5,9,15,45)
Hence, a = 3 and b = 5
Answered by Anonymous
1

a^2*b*2*7=630

a^2*b=45

45 = (1,3,5,9,15,45)

Hence, a = 3 and b = 5

thanku

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