if a and b are two odd number show that (α2-b2) is composite
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Answer:
let a=5 and b=3
=(2×5-2×3)
=(10-6)
=4.
Showed that 2a-2b =4
Answered by
0
Answer:
(a^2-b^2) = (a-b)(a+b)
Now, a and b are 2 odd prime numbers and the difference of 2 odd numbers is an even number. Also, the sum of 2 odd numbers is always even.
Hence, (a-b) and (a+b) are both even numbers and hence are atleast divisble by 2.
So, 2 is a factor of (a^2-b^2) and hence (a^2-b^2) is a composite number.
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