If a and b are two odd prime numbers show that a2-b2 is composite
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if u subtract any 2 odd numbers u get a composite number if it's square of them also it stays as composite number
It's too short... Not at all helpful
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Answer:
Step-by-step explanation:
The difference of any two odd numbers is even and also the sum of any two odd numbers is always even....
a^2-b^2=(a+b) (a-b)
And hence from the above explanation we can say that (a+b) &(a-b) are even numbers and are atleast divisible by 2
Therefore, 2is a factor of a^2 -b^2
And hence a^2-b^2 is a composite number
Similar questions
Now, a and b are 2 odd prime numbers and the difference of 2 odd numbers is an even number. Also, the sum of 2 odd numbers is always even.
Hence, (a-b) and (a+b) are both even numbers and hence are atleast divisble by 2.
So, 2 is a factor of (a^2-b^2) and hence (a^2-b^2) is a composite number.