Question

If a and b are two rational numbers then find the value of a and b in following

equations

(i) 6+√3 ÷ 6-√3 = a+b√3​

Answer 1

Step-by-step explanation:

ANSWER

3

−

2

3

+

2

=a+b

6

(

3

−

2

)(

3

+

2

)

(

3

+

2

)

2

=a+b

6

3−2

3+2+2

6

=a+b

6

5+2

6

=a+b

6

a=5 & b=2

Answer 2

Answer:

a = 13/11, b = 4/11

Step-by-step explanation:

6+√3÷6-√3 = a+b√3

Now on solving LHS, we get,

6+√3/6-√3 = (6+√3)^2/(6)^2- (√3)^2 = 36+3+12√3/36-3 = 39+12√3/33 = 3(13+4√3)/33

= 13+4√3/11

Now comparing LHS with RHS, we get

a= 13/11 and b = 4/11