Question

If A and B are two sets so that n(B−A) = 2n(A−B) = 4n(A∩B) and if n(A∪B) = 14 , then find n(P(A)).

Answer 1

Answer:

hello friend here ur answer

Step-by-step explanation:

n(p(A))=n(A-B) /n(AnB)

Answer 2

Answer:

Step-by-step explanation:

To find n(P(A)), we need n(A).

Let n(A ∩ B) = k. Then n(A − B) = 2k and n(B − A) = 4k.

Now n(A ∪ B) = n(A − B) + n(B − A) + n(A ∩ B) = 7k.

It is given that n(A ∪ B) = 14. Thus 7k = 14 and hence k = 2.

So n(A − B) = 4 and n(B − A) = 8. As n(A) = n(A − B) + n(A ∩ B), we get n(A) = 6 and

hence n(P(A)) = 26 = 64.