Question

if A and B are two sets such that a has 19 elements Bihar 17 elements and a intersection b has 10 elements how many elements does a union B have​

Answer 1

Answer:

$n(a) = 19. \\ n(b) =17 \\ \\ n(anb) = 10. \\ \\ n(aub) = n(a) + n(b) - n(anb) \\ \\ \: \: \: = 19 + 14 - 10 \\ \\ = 33 - 10 \\ \\ = 23$

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