Question

If a and b are two sets such that n(a)=38, n(b)=42 and n(aub)=60 find n(anb)

Answer 1

$\huge\green {\underline {\mathfrak {Answer:}}}$

$\underline {\bold{\pink{Given:}}}$

➣$n(A) = 38$

➣$n(B) = 42$

➣$n(A \cup B) = 60$

$\underline {\bold{\pink {Find:}}}$

➣$n(A \cap B)$

$\underline {\bold {\pink{Solution:}}}$

✦$\mathcal{\color{gold}{By \ formula:}}$

➫$n(A \cup B) = n(A) + n(B) - n(A \cap B)$

➫$60 = 38 + 42 - n(A \cap B)$

➫$n(A \cap B) = 80 - 60$

$\color{cyan}{\boxed{\implies{\boxed{\color{red}{n(A \cap B) = 20}}}}}$

Answer 2

Answer:

the ans is option b) 20

Step-by-step explanation: