Question

If A and B are two sets such that
n(A-B)=24, n(B-A)=19 and
n(ANB)=11 then find
(i) n(A), (ii) n(B), (iii) n(AUB).​

Answer 1

Answer:

Step-by-step explanation:

n(A-B)=24, n(B-A)=19 and

n(A∩B)=11

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(I) n(A-B)=n(A)-n( A∩B)

so 11=n(A) -11

n(A)=11+11=22

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(ii) n(B−A)=n(B)-n(A∩B)

So 19=n(B)-11

n(B)=19+11=30

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(iii) n( A∪B) =n(A)+n(B)-( A∩B)

n( A∪B)=22+30-11=52-11=41