If A and B are two sets such that n(A-B)= 45 , n(B-A)=23 and n(A∩B)=9
Then find n(A), n(B) and n(A∪).
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Answer:
n (a-b)=20+x
n(b-a)=3x
n(a n b ) =x+1
we know that
n(a-b) =n (a) - n(a n b)
therefore n(a) = n(a-b) + n( a n b)
3x + ( x+1)
4x+1
according to the question
n (a) = n (b)
therefore 2x +21 = 20
therefore x = 10
still there are any doubts ask in comments section oppas
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