Math, asked by preetywayenbam, 11 months ago

if a and b are two unequal rational numbers, show that a+b by2 rational number lying between a and b​

Answers

Answered by yugiarora
10

Answer:

a+b/2 is the average

Step-by-step explanation:

a+b/2 is the average and therefore has to be between them!!

It is also equal to a-b/2 + b


preetywayenbam: wrong
preetywayenbam: thxxx
Answered by isyllus
15

Given : two number a and b

To show : \frac{a+b}{2}rational number lying between a and b​

Step-by-step explanation:

let the two numbers be a and b where a <b

then

\frac{a+b}{2}-a = \frac{b-a}{2}&gt;0\\\\thus\\\\a&lt;\frac{a+b}{2}\\\\b - \frac{a+b}{2}= \frac{b-a}{2}= \frac{b-a}{2}&gt;0\\\\thus \\\\\frac{a+b}{2}&lt;b\\\\therefore \\\\a&lt;\frac{a+b}{2}&lt;b

hence ,  \frac{a+b}{2} is the rational number lie between the rational numbers a and b

#Learn more :

https://brainly.in/question/16562917

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