Question

If a and b are two vectors such that magnitude of A =4 magnitude of b= 1/2 and vector a×vector b = -1, find the angle between a and b.​

Answer 1

Answer:

angle ie theta is 5π/6

Explanation:

sin theta = |a×b|/ |a| |b|

= -1 / 4× 1/2

= -1 / 2

sin theta = -1/ 2

theta = sin ^-1 ( -1/2)

= sin ^-1 ( sin 5π/6)

5π/6