If a and b are zeroes of 2x²+5x+K,find K
if (a+b)whole square-ab=24.
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Dont copy answer cuz its not imported that my answer is correct but the way of doing the question is correct. I hope u understand the answer.
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Let me take the zeroes as α and β.
Consider a polynomial p(x) = ax² + bx + c whose zeroes are α and β. Then,
→ α + β = -b/a
→ αβ = c/a
Let p(x) = 2x² + 5x + k = 0.
A = 2 ; B = 5 ; C = k
Let the zeroes be a and b.
a + b = -5/2 ; ab = k/2
So, it may be,
(a + b)² - ab = 24
(-5/2)² - k/2 = 24
25/4 - 2k/4 = 24
(25 - 2k)/4 = 24
25 - 2k = 4 · 24
25 - 2k = 96
k = (25 - 96)/2
k = - 71 / 2
Hence found!
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