If a and b are zeroes of 2x² + 5x + k find the value of k such that (a+b)²-ab = 24
answer is -71/2
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Given :
- α and β are zeroes of 2x² + 5x + k.
- (α + β)² - αβ = 24
To find :
- Value of k =?
Formula Used :
- f(x) = ax² + bx + c.
- Sum of roots = -b/a
- Product of roots = c/a
Step-by-step explanation :
2x² + 5x + k
a = 2
b = 5
c = k
f(x) = ax² + bx + c
Sum of roots, α + β = -b/a = - 5/2
Product of roots, αβ = c/a = k/2
According to the question,
(α + β)² - αβ = 24
(-5/2)² - k/2 = 24
25/4 - k/2 = 24
25 - 2k/4 = 24
25 - 2k = 24 × 4
25 - 2k = 96
-2k = 96 - 25
-2k = 71
k = 71/-2
Or, k = - 71/2
Therefore, Value of k = - 71/2.
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